A 400v, 4-Pole,
50z, 3-Phase, 10hp, Y-Connected induction motor has a no load slip of 1% and
full load slip of 4%. Find the following:
(i) Syn. Speed (ii) No load
speed (iii) Full load speed (ix) Frequency of rotor current at full
load (v) Full load torque.
Solution-6:
Here,
Pout
= 10hp = 10*746 = 7460Watt, Pole, P = 4, f = 50Hz, VL =400v
No load
slip, s =0.01, Full load slip, sfl = 0.04
(i) Syn. Speed
NS = 120f/P = 120*50/4 = 1500rpm
(ii) No load speed
NO = NS(1-s) = 1500(1-0.01) = 1485rpm
(iii)
Full load speed, NFL = NS(1- sfl) = 1500(1-0.04) = 1440rpm
(ix)
Frequency of rotor current, fr = sfl .f = 0.04*50 = 2Hz
(v) Full
load torque, Tsh = 9.55Pout/NFL =
9.55*7460/1440 = 48.78Nm
EEE Job Math-6
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