What is the full load current of a 50
HP, 50Hz, 0.85 pf induction motor when the line voltage is 415 V
Solution:
Here,
P = 50HP =
50*746 = 37300 Watt
Power Factor,
cos θ =
0.85
Line Voltage, VL = 415
P = √3 VL IL cos θ
IL = P / ( √3
VL cos θ ) = 37300/ (√3 *415*0.85) = 61.04A (Ans)
EEE Job Math-4
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good post...
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