A
400V, 10hp, 4 pole, 5 0Hz, Y-connected induction motor operates at full load
speed of 5%. Determine the synchronous speed, rotor speed and shaft torque at
this operating condition.
Solution:
Here, frequency, f= 50Hz
Number of poles, P= 4
Slip, s= 5% = 0.05
We know that,
Synchronous speed, Ns = 120f/P = 120x50/4 = 1500 rpm
Rotor speed, Nr = (1-s)Ns =
(1-0.05)1500 = 1425 rpm
Shaft Torque, τshaft = Pout /ωm = (10x746)/{Nr x (2π/60)} =
7460/(1425x 0.1256) = 50Nm
EEE Job Math-1
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